110 Oakwood Circle, Bristol, CT 06010
- 4 beds |
- 3 baths |
- 2,534 sqft
Single-Family Home
Built in 2005
0.81acre lot
2 car garage
$168/sqft
Listed 10 days ago
Property Description
Welcome to 110 Oakwood Circle, a Colonial that blends classic charm with everyday functionality, set in a quiet Bristol neighborhood with lovely views. Step inside to a bright and inviting main level where hardwood floors and abundant natural light create a warm, open feel. The kitchen is the heart of the home, featuring granite counters, stainless steel appliances, and a seamless flow into the dining area and living room, where a cozy gas fireplace anchors the space. Sliders lead out to a spacious patio overlooking the wooded backyard, creating a peaceful, private retreat perfect for morning coffee or relaxed evenings. Upstairs, the primary suite offers a comfortable escape with a walk in closet and a private bath featuring double sinks and a shower. The additional bedrooms are generously sized, including an oversized third bedroom that doubles as a massive bonus space ideal for a recreation room, home office, or flex living area. The lower level adds even more versatility with walk out access and room for a gym, media space, or additional storage. With central air, an attached garage, and a well kept exterior, this home delivers both convenience and comfort in a desirable location close to local amenities, highways, and everyday essentials.
- Listing Status:
- Active
- Date Added:
- May 1, 2026
- Data Last Updated:
- May 12, 2026 at 4:53AM
- Listing Office:
- KW Legacy Partners : (860) 313-0700
- Listing Agent:
- Ginger Glovna : (203) 605-8725
- MLS ID:
- 24160073

- General: Patio
- Style: Colonial
- Parking: Parking spaces: 4
- Roofing: Asphalt ShingleGable
- County: Hartford
- Driveway: Private
- Zoning: R-25486082
- Water: Public Water Connected
- Sewer: Public Sewer Connected
This listing courtesy of Ginger Glovna , KW Legacy Partners
Monthly Payment
- Principal & Interest $
- Property Taxes $
- Home Insurance $
- VA Funding Fee $






