2005 S Finley Road 212, Lombard, IL 60148
- 2 beds |
- 2 baths |
- 1,080 sqft
Condominium
Built in 1975
—— sqft lot
—— car garage
$234/sqft
Listed 2 days ago
Property Description
Experience the perfect blend of luxury, craftsmanship, and modern design in this beautifully renovated 2-bedroom, 2-bath condo. The custom-built solid wood cabinetry features soft-close doors and drawers, paired with elegant imported Italian porcelain tile and stunning quartz countertops that create a timeless, sophisticated look throughout the home. The beautifully designed bathrooms offer a true spa-like retreat with high-end finishes that must be seen in person to be fully appreciated. Every detail has been thoughtfully selected to deliver exceptional quality and style. Step outside onto your private balcony and unwind while enjoying breathtaking sunset views. With a private balcony accessible from each bedroom and the living area, this home offers the perfect setting to relax, entertain, and enjoy peaceful evenings. This is a rare opportunity to own a move-in-ready home where luxury, comfort, and attention to detail come together seamlessly.
- Listing Status:
- Active
- Data Last Updated:
- August 24, 2026 at 12:19PM
- Listing Office:
- HomeSmart Connect LLC : 847-702-6337
- Listing Agent:
- Nazee Hamidi : 847-702-6337
- MLS ID:
- 12740133

- General: Balcony
- Parking: AsphaltUnassignedGuestYesParking spaces: 2
- Roofing: Tar/Gravel
- HOA Amenities: Coin LaundryElevator in ResidenceExercise RoomStorageHealth ClubOn Site Manager/EngineerParty RoomPoolSecurity Door Lock(s)WaterParkingInsuranceTV/CableClubhouseExercise FacilitiesPoolExterior MaintenanceLawn CareScavengerSnow Removal538.0Monthly
- Originating MLS: mred
- School District: 44
- County: DuPage
- Zoning: 0619404024
- Utilities: 100 Amp Service
- Water: Lake Michigan
- Sewer: Public Sewer
- Source: mred
- Ownership: Condo
This listing courtesy of Nazee Hamidi , HomeSmart Connect LLC
Monthly Payment
- Principal & Interest $
- Property Taxes $
- Home Insurance $
- VA Funding Fee $






