4879 Larkspur Drive, Plainfield, IN 46168
- 2 beds |
- 2 baths |
- 1,463 sqft
Single-Family Home
Built in 2021
7,405sqft lot
2 car garage
$188/sqft
Listed 4 months ago
Property Description
Welcome to easy living in one of Plainfield's most desirable 55+ active adult communities! Built in 2021, this beautifully maintained ranch home offers the perfect blend of comfort, convenience, and low-maintenance living. Featuring 2 bedrooms, 2 full baths, and an open-concept layout, this home is designed for both everyday comfort and effortless entertaining. The bright and inviting kitchen opens seamlessly to the spacious living and dining areas, creating a warm and welcoming atmosphere for gatherings with family and friends. The private primary suite includes a walk-in closet and en-suite bath designed for comfort and functionality. Enjoy peaceful mornings with coffee on the patio and spend more time enjoying life with exterior maintenance and lawn care handled for you. Whether you are looking to downsize, simplify, or enjoy a more active lifestyle, this home offers the perfect opportunity to enjoy the next chapter without the upkeep of a larger property. Located in a sought-after 55+ community offering walking trails, social activities, clubhouse amenities, and convenient access to shopping, dining, healthcare, and the Indianapolis airport. Move-in ready and available for immediate possession!
- Listing Status:
- Active
- Data Last Updated:
- May 20, 2026 at 3:18PM
- Listing Office:
- F.C. Tucker Company : 317-270-4898
- Listing Agent:
- Matt Steward : 317-270-4898
- MLS ID:
- 22077604

- Style: Ranch
- Parking: Attached
- General: OneSlab
- HOA Amenities: 238.0Monthly
- Originating MLS: mibor
- School District: Plainfield Community School Corp
- County: Hendricks
- Zoning: Vandalia By Del Webb Sec 6 Lot 153 0.166Ac (Plat)321032235023000029
- Water: Public
- Source: mibor
This listing courtesy of Matt Steward , F.C. Tucker Company
Monthly Payment
- Principal & Interest $
- Property Taxes $
- Home Insurance $
- VA Funding Fee $






