5150 South Jones Boulevard 108, Las Vegas, NV 89118
- 2 beds |
- 2 baths |
- 920 sqft
Condominium
Built in 1989
7,131sqft lot
—— car garage
$215/sqft
Listed 18 hours ago
Property Description
Welcomе to thіs beautifullу uрdated fіrѕt-floor condo in thе gatеd Alexis Heights community! This move-in-ready 2-bedroom, 2-bath home offers 920 sq. ft. with a bright, open floor plan designed for comfortable everyday living. Step inside to a clean, inviting interior featuring attractive flooring, a spacious living area and a well-designed kitchen with plenty of cabinet and counter space. The two-bedroom layout provides excellent privacy, making it ideal for a primary residence, second home or investment property. Enjoy the convenience of in-unit laundry and a private patio area perfect for relaxing outdoors. Alexis Heights offers a resort-style setting with gated access, community pools and spas, fitness center, mature landscaping and beautiful green spaces. The community is centrally located with convenient access to shopping, dining, entertainment, freeways and the world-famous Las Vegas Strip. Fantastic location, gated community and a desirable first-floor location—this Las Vegas condo is ready for its next owner!
- Listing Status:
- Active
- Data Last Updated:
- August 13, 2026 at 10:16PM
- Listing Office:
- Simply Vegas : 702-685-3000
- Listing Agent:
- Jim Wicklund : (702) 349-8180
- Contact:
- (702) 349-8180
- MLS ID:
- 2808212

- General: None
- Style: Two Story
- Pool: Community
- Parking: AssignedCoveredDetached Carport
- Roofing: Tile
- Windows: Blinds
- General: Drywall2
- HOA Amenities: ClubhouseFitness CenterPoolSpa/Hot TubSewerSecurityTrashWater310.0Monthly
- Originating MLS: GLVAR_LAS
- County: Clark
- Zoning: 163-25-210-056
- Fencing: None
- Utilities: Cable AvailableUnderground UtilitiesPhotovoltaics None
- Water: Public
- Sewer: Public Sewer
- Source: GLVAR_LAS
This listing courtesy of Jim Wicklund , Simply Vegas
Monthly Payment
- Principal & Interest $
- Property Taxes $
- Home Insurance $
- VA Funding Fee $






