15 Glengary Drive, Delaware, OH 43015
- 3 beds |
- 3 baths |
- 1,512 sqft
Single-Family Home
Built in 1997
0.37acre lot
2 car garage
$212/sqft
Listed 3 days ago
Property Description
This inviting three-bedroom, two-and-a-half-bath home at 15 Glengary Drive offers a perfect blend of comfort and functional design within the peaceful Kensington Place neighborhood of Delaware, Ohio. Spanning over 1,500 square feet, the residence features a bright and open layout equipped with central air conditioning and ceiling fans to ensure year-round comfort. The heart of the home is a fully equipped kitchen featuring a dishwasher and refrigerator, making daily meal preparation and entertaining a breeze. Each of the three bedrooms provides ample space for relaxation, while the attached garage offers convenient parking and additional storage options. Extending the living space outdoors, the property features a private backyard that provides a quiet retreat for gardening or weekend gatherings. Built in 1997, this well-maintained property sits just moments away from the 15-acre Kensington Place Park, offering easy access to open green spaces and walking paths. With its prime location near local schools, shopping, and the charming amenities of downtown Delaware, this home provides a serene yet highly connected lifestyle for its next owners
- Listing Status:
- Active
- Date Added:
- April 28, 2026
- Data Last Updated:
- May 1, 2026 at 6:36PM
- Listing Office:
- Rasmus Real Estate Group, Inc. : 470-412-9357
- Listing Agent:
- Jude A Rasmus : 470-412-9357
- MLS ID:
- 226014214
- General: Bi-LevelPoured
- HOA Amenities: Common Area Only100.0
- Originating MLS: Columbus and Central Ohio Regional MLS
- School District: DELAWARE CSD 2103 DEL CO.
- County: Delaware
- Zoning: 519-441-03-009-000
- Water: Public
- Sewer: Public Sewer
- Source: Columbus and Central Ohio Regional MLS
This listing courtesy of Jude A Rasmus , Rasmus Real Estate Group, Inc.
Monthly Payment
- Principal & Interest $
- Property Taxes $
- Home Insurance $
- VA Funding Fee $






