735 Vernon Ave, Kenilworth Boro, NJ 07033
- 5 beds |
- 4 baths
Single-Family Home
Built in 2026
7,405sqft lot
2 car garage
$——/sqft
Listed 21 days ago
Property Description
Exceptional fully reconstructed home in Kenilworth offering outstanding design, generous living space, and quality craftsmanship throughout. Featuring 5 bedrooms and 4.5 baths, this thoughtfully designed home offers the perfect blend of style, comfort, and flexibility.The main level features a desirable first-floor bedroom with a private full bath, ideal for guests, extended living, or a private home office. A formal living room and dining room lead to a spacious family room that flows seamlessly into the beautifully appointed kitchen, with direct access to the yard perfect for both everyday living and entertaining.Upstairs, the impressive primary suite features a spa-inspired bath and generous walk-in closet. Additional bedrooms are spacious with ample storage, along with a conveniently located second-floor laundry.Additional highlights include a full attic for storage, attached two-car garage, multi-zone heating and central air, and plenty of storage throughout.Conveniently located near transportation, major highways, schools, shopping, and the center of town. A rare opportunity to own a beautifully reconstructed home offering space, versatility, and modern amenities in Kenilworth! SELLER offering Financing
- Listing Status:
- Active
- Data Last Updated:
- October 26, 2026 at 4:40PM
- Listing Office:
- MICHELLE DAVID REALTY GROUP : 908-276-6299
- MLS ID:
- 4056856
- General: Vinyl SidingStorage ShedThermal Windows/Doors
- Style: Custom HomeColonial
- Parking: Parking spaces: 4
- Roofing: Asphalt Shingle
- County: Union
- Driveway: 2 Car WidthBlacktopDriveway-ExclusiveOff-Street Parking
- Zoning: 2908-00158-0000-00010-0000-
- Utilities: ElectricGas-Natural
- Water: Public Water
- Sewer: Public Sewer
This listing courtesy of MICHELLE DAVID REALTY GROUP
Monthly Payment
- Principal & Interest $
- Property Taxes $
- Home Insurance $
- VA Funding Fee $






